Notăm cele două numere cu a și b.
[tex]\it a-b= \dfrac{4}{9}\ \ \ \ \ (1)\\ \\ b=\dfrac{2}{3}\ din\ a \Rightarrow b=\dfrac{2}{3}\cdot a\ \ \ \ \ (2)\\ \\ (1),\ (2) \Rightarrow a-\dfrac{2}{3}\cdot a=\dfrac{4}{9} \Rightarrow a\cdot\Big(1-\dfrac{2}{3}\Big)=\dfrac{4}{9} \Rightarrow a\cdot \dfrac{1}{3}=\dfrac{4}{9} \Rightarrow \\ \\ \Rightarrow a=\dfrac{4}{9}:\dfrac{1}{3} \Rightarrow a=\dfrac{4}{9}\cdot\dfrac{3}{1} \Rightarrow a=\dfrac{\ 12^{(3}}{9}\Rightarrow a= \dfrac{4}{3}\ \ \ \ \ (3)[/tex]
[tex]\it (2),\ (3) \Rightarrow b=\dfrac{2}{3}\cdot \dfrac{4}{3} \Rightarrow b= \dfrac{8}{9}\\ \\ \\ Numerele\ cerute\ sunt\ :\ \ a=\dfrac{4}{3},\ \ \ b=\dfrac{8}{9}[/tex]
