24+3×{16+5×[Z14+2×(44÷a+6)-32]-24}-20=10
sau macar sa mi explice cineva cum se rexolva astel de exercitii
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Deci mereu cand ai calcul din asta dai dintr-o parte in alta de exemplu

24+3×{16+5×[14+2×(44÷a+6)-32]-24}-20=10 /+20

24+3×{16+5×[14+2×(44÷a+6)-32]-24}=30 /-24

3×{16+5×[14+2×(44÷a+6)-32]-24}= 6 /:3

16+5×[14+2×(44÷a+6)-32]-24=2 /+24

16+5×[14+2×(44÷a+6)-32]=26 /-16

5×[14+2×(44÷a+6)-32]=10 /:5

14+2×(44÷a+6)-32=2 /+32

14+2×(44÷a+6)=34 /-14

2×(44÷a+6)=20 /:2

44÷a+6=10 /-6

44÷a=4 =>a=44÷4=11

Explicație pas cu pas:

acolo unde scrie Z14 am lasat 14

Răspuns:

a = 11

Explicație pas cu pas:

24+3×{16+5×[14+2×(44÷a+6)-32]-24}-20 = 10

3×{16+5×[14+2×(44÷a+6)-32]-24} = 10+20-24

3×{16+5×[14+2×(44÷a+6)-32]-24} = 6

{16+5×[14+2×(44÷a+6)-32]-24} = 2

5×[14+2×(44÷a+6)-32] = 2-16+24

5×[14+2×(44÷a+6)-32] = 10

[14+2×(44÷a+6)-32] = 2

2×(44÷a+6)-32] = 2+32-14

2×(44÷a+6) = 20

(44÷a+6) = 10

(44÷a+6) = 4

44÷a = 10-6

44÷a = 4

a = 44÷4

a = 11