Răspuns:
[tex]2 \sqrt{2} \times ( \sqrt{6} - \sqrt{10} ) - 4 \sqrt{3} + 4 \sqrt{5} = \\ 2 \sqrt{12} - 2 \sqrt{20} - 4 \sqrt{3} + 4 \sqrt{5} = \\ 2 \times 2 \sqrt{3} - 2 \times 2 \sqrt{5} - 4 \sqrt{3} + 4 \sqrt{5} = \\ 4 \sqrt{3} - 4 \sqrt{5} - 4 \sqrt{3} + 4 \sqrt{5} = \\ = 0[/tex]