Răspuns:
Explicație:
a. NaOH
M= 23 +16 =1=40-----> 40g/moli
40 g NaOH---------23g Na----------16g O ---------1g H
100 g-------------------x---------------------y-----------------z
x= 100 . 23 : 40=57,5%Na
y=100 . 16 : 40=40% O
z= 100 . 1 : 40=2,5% H
b. Ca(OH)2
M= 40 + 2.16 +2=74------> 74g/moli
74g---------40 g Ca -------32g O---------2g H
100------------x---------------------y--------------z
x= 100 .40 : 74=54,05%Ca
y= 100 . 32 : 74=43,24% O
z= 100 .2 : 74=2,71% H
c. NH3
M= 14 +3=17-----> 17g/moli
17g NH3---------14g N---------3gH
100g --------------x------------------y
x= 100 . 14 : 17=82,35% N
y= 100 . 3 : 17=17,65% H
d. NH4OH
M=14 + 5 + 16=35-------> 35g/moli
35g NH4OH-------14gN---------5gH---------16gO
100g----------------------x-------------y--------------z
x= 100 . 14 : 35=40% N
y= 100 . 5 : 35=14,29% H
z= 100 . 16 : 35=45,71% O
