stiind ca a supra b egal cu 6 calculati 2a minus b supra 3a plus b



Răspuns :

[tex]\frac{a}{b}=6 => a=6b\\\frac{2a-b}{3a+b} = \frac{2*6b-b}{3*6b+b} =\frac{11b}{19b} =\frac{11}{19}[/tex]