Calculează:
a) 18 g +36 dag = ? dg
30 dg + 72 g = ?g
49 kg -210 dag = ? hg
67 hg-100 dg = ? dag
b) 8 x 50 cg + 6 x 250 dg = ?g
20000g:4-20x 1500 dg = ? hg
8q-(2x 650 dag +4x 750 g) 50 = ? kg
9t+ [500 q-(500 kg-5 800 hg) x 9] = ?
Repede vă rog!!​

Răspuns:

Salut :}

a) 18 g +36 dag = ? dg

18 g = 180 dg

36 dag = 3600 dg

180 dg +3600 dg = 3780 dg

30 dg + 72 g =? g

30 dg = 3 g

3 g + 72 g =75 g

49 kg - 210 dag =? hg

210 dag = 21 hg

49 kg = 490 h

67 hg - 100 dg = ? dag

67 hg = 670 dag

100 dg = 1 dag

670 dag - 1dag = 669 dag

b) 8×50 cg +6× 250 dg=? g

50 cg = 5 g

250 dg = 25 g

8×5 g+ 6×25 g=

40g + 150 g = 190 g

20000 g ÷ 4 - 20 × 1500 dg = ? hg

20000 g = 200 hg

1500 dg = 15 hg

200 hg : 4 - 20 × 15bhg =

50 hg - 300 hg = 250 hg

8 q -( 2×650 dag + 4 × 750 g) 50 = ? kg

800 kg - (1300 dag +3000 g ) × 50 =

800 kg - ( 13 kg + 3kg)× 50=

800 kg - 16 kg × 50 =

800 kg - 800 kg = 0 kg

9 t+ [500 q -(500 kg - 5× 800 hg ) ×9]=? q

90 q + [500q-(500 kg - 4000 hg) × 9 ]=

90 q + [500 q -( 500 kg - 400 kg ) × 9]=

90 q +( 500 q - 100kg × 9 ) =

90 q + (500 q -900 kg)=

90 q + (500 q - 9 q) =

90 q + 491 q = 581 q

Baftă!