[tex](-2)^{6} \cdot(-3+(15-4)):2^{8}=\\\\(2)^{6} \cdot(-3+11):2^{8}=\\\\(2)^{6} \cdot8:2^{8}=\\\\(2)^{6} \cdot 2^{3}:2^{8}=\\\\2^{6+3-8}=\\\\\boxed{2^{1} } =\\\\\boxed{2}[/tex]
Răspuns: 2
Cateva formule pentru puteri:
- (- a)ⁿ, unde n este o putere para (-a)ⁿ = aⁿ
- aⁿ · aᵇ = (a · a) ⁿ ⁺ ᵇ sau (a · a) ⁿ ⁺ ᵇ = aⁿ · aᵇ
- aⁿ : aᵇ = (a : a) ⁿ ⁻ ᵇ sau (a : a) ⁿ ⁻ ᵇ = aⁿ : aᵇ
- aⁿ · bⁿ = (a · b)ⁿ sau (a · b)ⁿ = aⁿ · bⁿ
- aⁿ : bⁿ = (a : b)ⁿ sau (a : b)ⁿ = aⁿ : bⁿ
- (aⁿ)ᵇ = aⁿ ˣ ᵇ sau aⁿ ˣ ᵇ = (aⁿ) ᵇ
