Răspuns:
{[(2¹³×5⁷)³÷(2³⁷×5¹⁹)-11×3²]×2⁵+1}÷[(2²^²×2³^³)÷(2⁵)⁶+(3⁵)³÷3¹³]
={[(2¹³×5⁷)³/2³⁷×5¹⁹ -11×9]×2⁵+1}÷[(2⁴×2³^³)÷2³⁰+3¹⁵÷3¹³]
={[(2⁶×10⁷)³/2³⁷×5¹⁹ -99]×2⁵+1}÷(2³¹÷2³⁰+3²)
=[(2¹⁸×10²¹/2³⁷×5¹⁹ -99)×2⁵+1]÷(2+9)
=[(2²¹×5²¹/2¹⁹×5¹⁹ -99)×2⁵+1]÷11
=[(2²×5²-99)×2⁵+1]÷11
={[(2×5)²-99]×2⁵+1}÷11
=[(10²-99)×2⁵+1]÷11
=[(100-99)×2⁵+1]÷11
=(1×2⁵+1)÷11
=(32+1)÷11
=33÷11
=3
Sper ca te-am ajutat :)
