Rezolvati urmatoarele ecuatii: a) 1,3 × X + 2,73 = 2 × (1,2 × X - 1) b) [tex]\frac{x}{2} + \frac{4}{9} = \frac{x +7}{6}[/tex] c) [tex]\frac{5Xx-1}{10} = \frac{2Xx-3}{6} + \frac{1}{3}[/tex] REZOLVARE DE CLASA A 6 A VA ROGGG DAU COROANA

Răspuns:

a)

1,3 × x + 2,73 = 2 × (1,2 × x - 1)

1,3x + 2,73 = 2,4x - 2

1,3 x - 2,4x = - 2 - 2,73

- 1,1x = - 4,73

x = - 4,73 : (-1,1)

x = 4,3

b)

[tex]\displaystyle \frac{x}2} \ + \ \frac{4}{9} \ = \ \frac{x + 7 }{6 } \ / \cdot 18 \\\\\\\displaystyle 9x \ + \ 8 \ = \ 3 \ \cdot \ (x \ + \ 7) \\\\\displaystyle 9x \ + \ 8 \ = \ 3x \ + \ 21 \\\\\\\displaystyle 9x \ - \ 3x \ = \ 21 \ - \ 8 \\ \\\displaystyle 6x = 13 \\\\\displaystyle x \ = \ \frac{13}{6}[/tex]

c)

[tex]\displaystyle \frac{5 \ \cdot \ x \ - \ 1}{10 } \ = \ \frac{2 \ \cdot \ x \ - 3 }{6} \ + \ \frac{1}{3} \ / \cdot 30 \\ \\\displaystyle 3 \ \cdot \ (5x \ - \ 1) \ = \ 5 \ \cdot \ (2x \ - \ 3) + \ 10 \\ \\\displaystyle 15x \ - \ 3 \ = \ 10x \ - \ 15 \ + \ 10\\ \\\displaystyle 15x\ - \ 10x\ \ = - 15 \ + \ 10 \ + \ 3 \\\\\displaystyle 5x \ = \ - 2 \\ \\\displaystyle x \ = \ - \ \frac{2}{5}[/tex]

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