va rog ajutatima urgent va dau corona si 50 de puncte da va rog am nevoie doar de b si c ​

Răspuns:

c) 2x+6=4x+2

6-2=4x-2x

4=2x

x=4:2=2

b)5x+2=32

5x=30

x=30:5

x=6

[tex](10^x)^5*100=(2^4*5^4)^8\\10^{5x}*10^2=(10^4)^8\\10^{5x+2}=10^{32}\\10^{5x}=10^{32-2}\\10^{5x}=10^{30}\\5x=30\\x=\frac{30}{5} =6[/tex]

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[tex](5^2)^{x+3}=5^{4x}*5^2\\5^{2(x+3)}=5^{4x+2}\\5^{2x+6}=5^{4x+2}\\2x+6=4x+2\\2x-4x=2-6\\-2x=-4/*(-1)\\2x=4\\x=\frac{4}{2} =2[/tex]