3/4 + 7/3 + 32/15 : 7/33 – 10/3 : 5/3 – 113/6= ?

Explicație pas cu pas:

[tex]\frac{3}{4}+\frac{7}{3} +\frac{32}{15}:\frac{7}{33} -\frac{10}{3}:\frac{5}{3} -\frac{113}{6}=\\\\\frac{3}{4}+\frac{7}{3} +\frac{32}{15}*\frac{33}{7} -\frac{10}{3}*\frac{3}{5} -\frac{113}{6}=\\\\\ \frac{3}{4}+\frac{7}{3} +\frac{32*11}{5*7} -\frac{2}{1}-\frac{113}{6}=\\\\\frac{105*3+140*7+352*12-420*1-113*70}{420} =\\\\\frac{315+980+4224-420-7910}{420} =\\\\\frac{5519-8750}{420}=\\\\\frac{-3231}{420} = \boxed{-\frac{1077}{140} }[/tex]

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Răspuns:

Explicație pas cu pas:

3/4 + 7/3 + 32/15 : 7/33 - 10/3 : 5/3 - 113/6 =

= 9/12 + 28/12 + 32/15 × 33/7 - 10/3 × 3/5 - 113/6 =

= 37/12 + (32×11)/(5×7) - 2 - 113/6 =

= 37/12 + 352/35 - 2 - 113/6 =

→ cel mai mic multiplu comun al numitorilor 12, 35 si 6 = 420

→ amplific fractia 37/12 cu 35, fractia 352/35 cu 12, iar fractia 113/6 cu 70

= 1295/420 + 4224/420 - 840/420 - 7 910/420 =

= (5519 - 8 750)/420 =

=-  3231/420 =

= - 1077/140